Question

The Kentucky Derby, the first leg of horse racing’s Triple Crown, was won by a time of 122.2 s. If the race covers 2011.25 m, what was the average speed in a) m/s and b) in mi/h?

20 Extra points! Please help

Answer 1

The answer is 789.25 which you’d subtract 2011.25-122.2 I think sry if I’m wrong

Answer 2

a)
`16.45 (m)/(s)` b)
`36.94 (mi)/(h)`

Step-by-step explanation:

The average speed is given by the formula:
`(distance)/(time)`

The distance covered is 2011.25m , and the time is 122.2s.

Replacing in the formula:
`speed_(avg) = (2011.25 m)/(122.2s)`

Resulting in a)
`speed_(avg) = 16.45 (m)/(s)`.

To get the result in mi/h, do the following conversion:

Knowing : 1 mi = 1603 m and 1 h = 3600 seg

• 
  `16.45( m)/(s)*((1mi)/(1603m ) ) *((3600s)/(1h) ) = 36.94(mi)/(h)`