Answer:
$135
Step-by-step explanation:
Given:
Total clients = 1700
Membership dues = $45
Increase in monthly dues = $1
Loss of clients per dollar increase = 7 clients
Thus,
let x be the number of dollar increases
therefore,
clients lost will be 7x
so the revenue function will be
f(x) = charges × Number of clients
or
f(x) = ( 45 + x ) × ( 1700 - 7x )
or
f(x) = 90000 - 315x + 1700x - 7x²
or
f(x) = 90000 + 1385x - 7x²
now,
for point of maxima or minima
differentiating with respect to x, we get
f'(x) = 0 + 1385 - 14x = 0
or
14x = 1385
or
x = 98.92 ≈ 98
thus,
to optimize the revenue from monthly dues the club should charge
( $45 + $90 ) = $135