118k views
3 votes
The filament of a lightbulb has a resistance of R0=12Ω at 20 ∘C and 140 Ω when hot. Part APart complete Part B In this temperature range, what is the percentage change in resistance due to thermal expansion? Express your answer using two significant figures. Rexpansion−R0R0R e x p a n s i o n − R 0 R 0 = 1100 %

1 Answer

3 votes

Final answer:

The percentage change in resistance of the tungsten filament due to thermal expansion is 1100%.

Step-by-step explanation:

The question involves the change in resistance of a tungsten filament in a lightbulb due to thermal expansion. The resistance of the filament increases as it gets hotter. To calculate the percentage change in resistance, we can use the formula:

Percentage Change in Resistance = (Rexpansion - R0) / R0 * 100%

Substituting the given values, we have:

Percentage Change in Resistance = (140Ω - 12Ω) / 12Ω * 100% = 1100%

User Brett DeWoody
by
7.8k points