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12 votes
Solve x + 4y = 14 and 3x + 3y = 15 by elimination

User Sungjun
by
6.0k points

2 Answers

10 votes

Answer:

(2, 3 )

Explanation:

Given the 2 equations

x + 4y = 14 → (1)

3x + 3y = 15 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 3x - 12y = - 42 → (3)

Add (2) and (3) term by term to eliminate x, that is

0 - 9y = - 27

- 9y = - 27 ( divide both sides by - 9 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting into (1)

x + 4(3) = 14

x + 12 = 14 ( subtract 12 from both sides )

x = 2

solution is (2, 3 )

User FooF
by
6.1k points
12 votes

Answer:

you have to subtract 3y and then you do the same on the other side, then you end up with two numbers where you divide them and that will be your result

Explanation:

User Nicebyte
by
5.6k points