Question

in tests on earth a lunar surface exploration vehicle (mass=5.90*103 kg) achieves a forward acceleration of 0.220m/s2. To achieve this same acceleration on themoon, thevehicle's engines must produce a drive force of 1.43*103N. What is the magnitude of the frictional force that acts on thevehicle on the moon?All I know is it has something to do with the formulaG=m1m2/r2. I figure the thefrictional force is th force opposing the drive force.Pleasehelp.I figured it out thanks!

Answer 1

132 N

Step-by-step explanation:

m = Mass

a = Acceleration

F = ma

Force on Earth

`F_E=5.9* 10^3* 0.22\\\Rightarrow F_E=1298\ N`

Force on Moon

`F_M=1430\ N`

Here, the effect of gravity is already compensated by the forces hence gravity will not have any effect.

Frictional force would be the difference between the two forces

`F_f=F_M-F_E\\\Rightarrow F_f=1430-1298\\\Rightarrow F_f=132\ N`

Frictional force is 132 N.