Answer:
a) 0.6561
b) 0.2916
c) 0.3439
Explanation:
We are given the following information:
Let us treat high level of contamination as our success.
p = P(High level of contamination) = P(success) = 0.10
n = 4
The, by binomial distribution:
![P(X=x) = \binom{n}{x}.p^x.(1-p)^(n-x)\\\text{where x is the number of success}](https://img.qammunity.org/2020/formulas/mathematics/college/6l8r9s5g0ss6taem02cklrbjeetsl2aetr.png)
a) P(No high level of contamination)
We put x = 0, in the formula.
![P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^(4) =0.6561](https://img.qammunity.org/2020/formulas/mathematics/college/xi0ld1ptpinw09wdlzmf7mkgqqt9o1cxnt.png)
Probability that no lab specimen contain high level of contamination is 0.6561
b) P(Exactly one high level of contamination)
We put x = 1, in the formula.
![P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^(3) =0.2916](https://img.qammunity.org/2020/formulas/mathematics/college/hy68uh2tvn5qahadwtkno7py4eme1jsbt1.png)
Probability that no lab specimen contain high level of contamination is 0.6561
c) P(At least one contains high level of contamination)
![p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439](https://img.qammunity.org/2020/formulas/mathematics/college/os5l1bxwryjgonoezfvrjrt3u0dtzm0798.png)
Probability that at least 1 lab specimen contain high level of contamination is 0.3439