Question

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.37 μC/m2. Another infinite sheet of charge with uniform charge density σ2 = -0.19 μC/m2 is located at x = c = 28 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 12 cm and x = 16 cm). What is Ex(P), the x-component of the electric field at point P, located at (x,y) = (6 cm, 0)?

Answer 1

The x-component of the electric field at point P -- 31,638.41

Step-by-step explanation:

Given data:

charge density
`\sigma_1 =0.37 \muC/m^2`

Another charge density
`\sigma_2 = -0.19 \mu C/m^2`

Electric field due to infinite sheet of charge is given as E

`E = (\sigma)/(2\epsilon)`

`E_(NET) = E_1 + E_2`

`= (\sigma_1)/(2\epsilon) + (\sigma_2)/(2\epsilon)`

`=  (0.37* 10^(-6))/(2* 8.85* 10^(-12)) + (0.19* 10^(-6))/(2* 8.85* 10^(-12))`

= 31,638.41