Question

The reaction of silver metal and dilute nitric acid proceeds according to the equation above. If 0.10 mole of powdered silver is added to 10.0 milliliters of 6.0 molar nitric acid, the number of moles of NO gas that can be formed is __________.

a) 0.015 mole

b) 0.020 mole

c) 0.030 mole

d) 0.045 mole

e) 0.090 mole

Answer 1

The answer to your question is: 0.015 mole of NO

Step-by-step explanation:

Data

Silver = Ag = 0.1 mole

Nitric acid = HNO3 = 10 ml 6 M

Balanced reaction

3Ag + 4HNO₃ ⇒ 3AgNO₃ + NO + 2H₂O

# moles of HNO₃ = 6(0.01) = 0.06

Limiting reactant HNO₃ because for the amount of silver given

the reaction needs 0.133 moles of acid, and there

are only 0.06

4 mol of HNO₃ ------------------- 1 mol of NO

0.06 mol of Ag ------------------ x

x = (0.06 x 1) / 4

x = 0.015 mol