Answer:
a) COCl₂.
b) The molecular formula is COCl₂.
Step-by-step explanation:
To obtain empirical formula of phosgene you should divide elemental compositions over atomic mass of each atom, and divide these results between the smallest, thus:
C = 12,14%/12,01 = 1,01
O = 16,17%/16 = 1,01
Cl = 71,69%/35,45 = 2,02
Empirical formula:
C = 1,01/1,01 = 1
O = 1,01/1,01 = 1
Cl = 2,02/1,01 = 2
C₁O₁Cl₂ ≡ COCl₂
b) You need to find the molar mass of the empirical formula to determine the ratio of the real formula, thus:
1×C 12,01g/mol =
1×O 16 g/mol =
2×Cl 35,35g/mol = 98,91g/mol
As real molecular mass is 98,9 g/mol. The molecular formula: COCl₂
I hope it helps!