Question

A stone is dropped into a deep well and hits the water after 3.41 seconds. How deep is

The well?

Answer 1

57.0 m

Step-by-step explanation:

Given:

v₀ = 0 m/s

t = 3.41 s

a = 9.8 m/s²

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²

Δx = 57.0 m