Question

CAN SOMEONE PLS HELP WITHT HSI ASAP

Answer 1

`x = ( √(6) )/(2)`

`y = (3 √(2) )/(2)`

Explanation:

`\sin(theta) = (opposite)/(hypotenuse)`

`\cos(theta) = (adjacent)/(hypotenuse)`

`\tan(theta) = (opposite)/(adjacent)`

theta = 30°

hypotenuse = √6

opposite = x

adjacent = y

1) find x using the sin formula

`\sin(theta) = (opposite)/(hypotenuse)`

`\sin(30) = (x)/( √(6) )`

`\sin(30) * √(6) = x`

`( √(6) )/(2) = x`

`x = ( √(6) )/(2)`

2) find y using the cos formula

`\cos(theta) = (adjacent)/(hypotenuse)`

`\cos(30) = (y)/( √(6) )`

`\cos(30) * √(6) = y`

`(3 √(2) )/(2) = y`

`y = (3 √(2) )/(2)`