34.8k views
20 votes
CAN SOMEONE PLS HELP WITHT HSI ASAP

CAN SOMEONE PLS HELP WITHT HSI ASAP-example-1
User Salomvary
by
8.8k points

1 Answer

0 votes

Answer:


x = ( √(6) )/(2)


y = (3 √(2) )/(2)

Explanation:


\sin(theta) = (opposite)/(hypotenuse)


\cos(theta) = (adjacent)/(hypotenuse)


\tan(theta) = (opposite)/(adjacent)

theta = 30°

hypotenuse = √6

opposite = x

adjacent = y

1) find x using the sin formula


\sin(theta) = (opposite)/(hypotenuse)


\sin(30) = (x)/( √(6) )


\sin(30) * √(6) = x


( √(6) )/(2) = x


x = ( √(6) )/(2)

2) find y using the cos formula


\cos(theta) = (adjacent)/(hypotenuse)


\cos(30) = (y)/( √(6) )


\cos(30) * √(6) = y


(3 √(2) )/(2) = y


y = (3 √(2) )/(2)

User HosseinK
by
8.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories