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Find the x- and y- intercepts of the line 3x-4y=12

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Answer:

see explanation

Explanation:

Given

3x - 4y = 12

To find the x- intercept let y = 0 in the equation and solve for x

3x - 4(0) = 12

3x = 12 ( divide both sides by 3 )

x = 4 ← x- intercept ⇒ (4, 0 )

To find the y- intercept let x = 0 in the equation and solve for y

3(0) - 4y = 12

- 4y = 12 ( divide both sides by - 4 )

y = - 3 ← y- intercept ⇒ (0, - 3 )

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