Question

A 45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦ with respect to the horizontal. The coefficient of kinetic friction between the snow and skis is 0.114. The skier’s speed after traveling 300 m along this slope is (in m/s):

Answer 1

v = 21.03 m/s

Step-by-step explanation:

given,

mass of skier = 45 kg

the slope of the snow = 10.0◦

coefficient of friction = 0.114

distance traveled = 300 m

speed = ?

Acceleration = g sin θ - µ g Cos θ

= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)

= 0.737 m/s²

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 0.737 × 300

v = 21.03 m/s

Speed of skier's after travelling 300 m speed is equal to 21.03 m/s