197k views
2 votes
The attending veterinarian would like you to administer a 22 mg/kg dosage of Cefazolin to a 67 pound dog that is about to have surgery. You find that the vial that has been reconstituted is empty and you need to make a new bottle. How much sterile water will you add to a 1 gram vial if you want the concentration to be 200 mg/ml?

1 Answer

1 vote

Answer:

5 milliliter of sterile water will be added to a 1 gram vial.

Step-by-step explanation:

Concentration of dosage required = 200 mg/ml

That is 200 mg of Cefazolin in 1 mL of solution.

1 mg = 0.01 g

1 mL = 0.001 L


200 mg/ml=(200* 0.001 g)/(0.001 L)=200 g/L

The for 1 grams of Cefazolin will be present in x liters of water.


(1 g)/(x)=200 g/L


x=(1 g)/(200 g/L)=0.005 L = 5 ml

5 milliliter of sterile water will be added to a 1 gram vial.

User Nikolay Georgiev
by
7.7k points