Question

The froghopper (Philaenus spumarius), the champion leaper of the insect world, has a mass of 12.3 mg. It can leave the ground with a speed as high as 4.0 m/s in the vertical direction. The jump itself lasts a mere 1.0 ms before the insect is clear of the ground. Assuming constant acceleration, find the force that the ground exerts on the froghopper during its jump.

Answer 1

0.0492 N force

Step-by-step explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

`v=u+at\\\Rightarrow a=(v-u)/(t)\\\Rightarrow a=(4-0)/(0.001)\\\Rightarrow a=4000\ m/s^2`

F=ma

`F=12.3* 10^(-6)* 4000\\\Rightarrow F=0.0492\ N`

The ground exerts 0.0492 N force on the froghopper during its jump.