Question

In the city of Blacksburg, the average consumption of electricity per household is 900 kWh per month. In the town of Springfield, the average consumption of electricity is 1,020 kWh per month. 1. Calculate the percent difference between the average consumption in the two towns.

Answer 1

The percentage difference between two countries is 12.5%

Step by Step Explanation:

Given:

Average consumption of electricity in Blacksburg city=900
`(k w h)/(m o n t h)`

Average consumption of electricity in Springfield=1020
`(k w h)/(m o n t h)`

To find:

Percentage difference between the average consumption in two towns

Solution:

According to the formula, percentage difference is calculated as

`\text { Percentage difference }=\frac{\text { Value of larger town-Value of smaller town }}{\text { sum value of two town/2 }} * 100`

Value of larger town=Average consumption of electricity in Springfield

=1020
`(k w h)/(m o n t h)`

Value of smaller town= Average consumption of electricity in Blacksburg

=900
`(k w h)/(m o n t h)`

Sum value of two towns=1020+900=1920

Substitute these values in the above equation we get

`\text { Percentage difference }=(1020-900)/(1920 / 2) * 100`
`=(120)/(960) * 100`

`=0.125 * 100`

`=12.5 \%`

Result:

Thus the percentage difference between the average consumption of electricity between two towns =12.5%