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Solve the system by elimination (show all work)

-2x +2y+3z=0,


-2x-y+z=-3,


2x+3y+3z=5

User Synxis
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1 Answer

4 votes

Answer:


[1, 1, 0]

Explanation:

{−2x + 2y + 3z = 0

{−2x - y + z = −3 ←

{2x + 3y + 3z = 5 ←

2y + 4z = 2 ↷

{−2x + 2y + 3z = 0 ←

{−2x - y + z = −3

{2x + 3y + 3z = 5 ←

5y + 6z = 5 ↷

{5y + 6z = 5

{2y + 4z = 2

[5y + 6z = 5]

{2y - 2⅖z = 2 >> New Temporary Equation

{2y + 4z = 2

____________

1⅗z = 0

___ _

1 1⅗


z = 0 [Plug this back into both equations above to get the y-term of 1, then plugging both z-term and y-term into all three equations at the very top, will give you the x-term of 1];
1 = y;
1 = x

I am joyous to assist you anytime.

User Mitzy
by
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