1 Answer

Anand G · Answer 1 · 2020-09-07T07:22:13+0000

Let H be the point where the height drawn from Q falls.

Focus on QHR. It is a right triangle with legs QH and 3 and hypothenuse 5.

We can find QH using the pythagorean theorem:

$QR^2-HR^2=QH^2 \implies 25-9=16=QH^2 \implies QH=4$

Now, focus on QHP. It is again a right triangle, and this time we know both legs (QH=4, PH = 6) and we're looking for the hypothenuse:

$PQ^2 = PH^2+QH^2 = 36+16=52\implies PQ = √(52)$

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