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Let B = −1 1 −3

0 2 3 . Compute the indicated matrix. (If this is not possible, enter DNE in any single blank). BTB

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Answer:

Remember that in the transpose matrix of the matrix A, the entry
a_(ij) of A will be the entry
a_(ji) of
A^T.

Then if


B=\left[\begin{array}{ccc}-1&1&-3\\0&2&3\end{array}\right],
B^T=\left[\begin{array}{ccc}-1&0\\1&2\\-3&3\end{array}\right]

Then


B^TB=\left[\begin{array}{ccc}1&-1&3\\-1&5&3\\3&3&18\end{array}\right]

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