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Which equation has the solutions x= 5 ± 2 square root 7 all over 3

1. 3x2 – 5x + 7 = 0
2. 3x2 – 5x – 1 = 0
3. 3x2 – 10x + 6 = 0
4. 3x2 – 10x – 1 = 0

User Bastes
by
8.3k points

2 Answers

2 votes

Answer:

D

Explanation:

Using the equation, you see that 3x^2-10x-1=0

the answer is d

User Manjabes
by
8.7k points
5 votes

Answer:

4. 3x^2 – 10x – 1 = 0

Explanation:

You can write the quadratic from the roots:

0 = (x - (5-2√7)/3)(x - (5+2√7)/3)

= (x -5/3)^2 -(2√7/3)^2

= x^2 - 10/3x +25/9 -28/9

= x^2 -10/3x -1/3

Multiplying by 3 gives ...

0 = 3x^2 -10x -1

Which equation has the solutions x= 5 ± 2 square root 7 all over 3 1. 3x2 – 5x + 7 = 0 2. 3x-example-1
User Sagin
by
7.7k points

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