Question

The active ingredient in toothpaste is sodium fluoride an anticavity agent. A 170. Gube

of toothpaste lists the concentration of sodium fluoride as 0.24%. How many grams of
sodium fluoride are in the toothpaste?

Answer 1

There are 0.408 grams of sodium fluoride in the toothpaste.

Why?

We know that there is 0.24% of sodium floride in a 170 grams toothpaste tube. Since the only information related to the toothpaste is its mass, we can assume that the 0.24% (concentration) is referring to the mass percent, and we can calculate it using the following equation:

`MassPercent=(MassSolute)/(MasSolution)*100(percent)`

Now, substituting the given information and calculating, we have:

`MassPercent=(MassSolute)/(MasSolution)*100(percent)`

`(MassPercent*MassSolution)/(100)=MassSolute(NaF)\\\\MassSolute(NaF)=(0.24*170g)/(100)=0.408g`

We have that there are 0.408 grams of sodium fluoride in the toothpaste.

Have a nice day!