Question

Anyone can help me to solve this?​

Answer 1

Here, We are given a side of a cube.. Since, it is a cube alk the sides are equal amd the formula for volume of cube is:

`\boxed{ \tt \: {side}^(3) }`

• Side = x+1

Volume of cube;

`\sf \longmapsto \: (x + 1)^(3)`

• Expand using the identity
• 
  `\boxed{ \tt {(a + b)}^(3) = {a}^(3) + {3a}^(2)b + {3ab}^(2) + {b}^(3) }`

`\sf \longmapsto \: {x}^(3) + {3x}^(2) * 1 + 3x * {1}^(2) + {1}^(3)`

• Calculate the product and evaluate all the powers

`\therefore \rm \: Area = {x}^(3) + {3x}^(2) + 3x + 1`

Answer 2

`volume = x^3+3x^2+3x+1`

Volume of a cube is given by a³ where a denotes side of a cube.

Here given side:

• x + 1

So, the volume:

• (x + 1)³

• (x + 1)(x + 1)(x + 1)

• (x² + x + x + 1)(x + 1)

• (x² + 2x + 1)(x + 1)

• x³ + x² + 2x² + 2x + x + 1

• x³ + 3x² + 3x + 1