Answer:
0.7158 Mol/L
Step-by-step explanation:
KHC8H4O4 + NaOH → H2O + KNaC8H4O4
KHC8H4O4 molar mass = 204.2212 g/mol
0.4536 g of KHC8H4O4 = 2.221 mMol (10^-3 mol)
volume = 31.26 mL - 0.23 mL = 31.03 mL
NaOH concentration = 2.221 mMol/31.03 mL = 2.221 Mol/31.03 L = 0.7158 Mol/L