Question

How do i solve for x. e(x+c)÷b=2

Answer 1

`x = (2b)/(e) - c`

Explanation:

e(x + c) ÷ b = 2 Do orders of operation

(ex + ec) ÷ b = 2 Distribute e into x and c

`(ex + ec)/(b) = 2` Divide ex + ec by b

`(b)(ex + ec)/(b) = 2(b)` Multiply both sides by b to cancel it out

ex + ec = 2b Subtract ec from both sides to get ex alone

- ec - ec

ex = 2b - ec Now you have ex alone

`(ex)/(e) = (2b - ec)/(e)` Divide both sides by e to x alone

`x = (2b)/(e) - c`