Answer:
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Step-by-step explanation:
During the motion of the rock while it is in downward motion we can say
![T - mg cos\theta = ma_c](https://img.qammunity.org/2020/formulas/physics/high-school/yn1kw0b351wjv2wspspqp8lri77w9g68sl.png)
since it is performing circular motion so we will have its acceleration towards its center
![T = mgcos\theta + ma_c](https://img.qammunity.org/2020/formulas/physics/high-school/t1eubitc87tke9aqabid9qiseaxsbdfkdq.png)
![a_c = (v^2)/(L)](https://img.qammunity.org/2020/formulas/physics/high-school/kckbczy6ixwsp5lzifq1fejycy7n8x9yjk.png)
![T = mgcos\theta + (mv^2)/(L)](https://img.qammunity.org/2020/formulas/physics/high-school/1vkozq8wtto32yksas0bxt711zs11ca6kq.png)
So at the lowest point of the path we can say
![T = mg + (mv^2)/(L)](https://img.qammunity.org/2020/formulas/physics/high-school/2ql6ofwc8o1sfpvfnafsocgxx8hwvful51.png)
so correct answer is
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.