Answer:
The correct answer is option C,
Explanation:
Hose-A fills 60 gallons of water in 15 minutes .
Rate of Hose-A at which it fills water truck =
![R_a=(60 gal)/(15 min)=4 gal/min](https://img.qammunity.org/2020/formulas/mathematics/middle-school/21o44t2rfqy0kyinh77h4qhrpr3jiayqiq.png)
Hose-B fills water truck , its function is given as:
y = 3x
Where y is the total number of gallons filled in x minutes.
Rate of Hose-B at which it fills water truck =
![R_b=(y gal)/(xmin)=(3x)/(x) gal/min=3 gal/min](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6flrxq1y074wtq3qrbeagdy8bjumrzrpek.png)
Difference in rates of both hoses:
![R_a-R_b=4 gal/min - 4gal/min = 1 gal/min](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fmox3ywg8t2bevx097oz8ghtzhbpbag1gm.png)
![R_a-R_b=1 gal/min](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uz2xb0qijut3be7435gnbs7v2zrjzuffat.png)
![R_a=R_b+1 gal/min](https://img.qammunity.org/2020/formulas/mathematics/middle-school/10zosqchsg30n9tnezgw2r6nx76q282qsm.png)
The rate of Hose A is 1 gallon per minute more than the rate of Hose B.