Answer:
The realistic domain of the function is 0 ≤ t ≤ 3 ⇒ answer (2)
Explanation:
- The function h(t) = -16t² + 144 represents the height, h(t), in feet, of an
object from the ground at t seconds after it is dropped
∵ h(t) = -16t² + 144
∵ At the beginning t = 0
- Substitute the value of t in the function
∴ h(0) = -16(0)² + 144
∴ h(0) = 144
* The object was on a height 144 when t = 0
* Lets find the time when the object reached the ground
- When the object reached the ground its height = 0
∵ h(t) = -16t² + 144
∵ h = 0
- Substitute the value of h in the function
∴ 0 = -16t² + 144
- Add 16t² to both sides
∴ 16t² = 144
- Divide both sides by 16
∴ t² = 9
- Take √ for both sides
∴ t = 3 seconds
* The object reached the ground after 3 seconds
∵ The domain of the function is the values of t
∴ The realistic domain of the function is 0 ≤ t ≤ 3