Answer:
Distance to appointment point = 5 miles
Explanation:
Let s be the distance to the appointment point,
We have Maria drove to a business appointment at 50mph in the morning.
Time taken in the morning
![t_m=(s)/(50)=0.02s](https://img.qammunity.org/2020/formulas/mathematics/high-school/75vr7t8ab38ojovu7wnz3vs705sv7xnivx.png)
Her average speed on the return trip in the afternoon was 40 mph.
Time taken in the afternoon
![t_a=(s)/(40)=0.025s](https://img.qammunity.org/2020/formulas/mathematics/high-school/qtpr56ai4k7wuy2tlm6qy0mtu40vpgedfe.png)
Given that the return trip took 1/4hr longer because of traffic.
That is
![t_a-t_m=(1)/(4)hr=0.025hr](https://img.qammunity.org/2020/formulas/mathematics/high-school/2ji22rbev2afwgq42c7z831rhkb2yy62pq.png)
Substituting
![t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles](https://img.qammunity.org/2020/formulas/mathematics/high-school/92shd2rflkhp5hzkowkof5ocxu0fhw0zgl.png)
Distance to appointment point = 5 miles