Question

If a ball is dropped from a height​ (H) its velocity will increase until it hits the ground​ (assuming that aerodynamic drag due to the air is​ negligible). During its​ fall, its initial potential energy is converted into kinetic energy. If the ball is dropped from a height of 720720 centimeters​ [cm], and the impact velocity is 3939 feet per second​ [ft/s], determine the value of gravity in units of meters per second squared ​[m/s2​].

Answer 1

9.801 m/s²

Step-by-step explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 39 ft/s

s = Displacement = 720 cm = 7.2 m

a = Acceleration

Converting to m/s

`39\ ft/s=(39)/(3.281)=11.88\ m/s`

Equation of motion

`v^2-u^2=2as\\\Rightarrow a=(v^2-u^2)/(2s)\\\Rightarrow a=(11.88^2-0^2)/(2* 7.2)\\\Rightarrow a=9.801\ m/s^2`

Acceleration of the ball is 9.801 m/s²