Answer: 0.48
Explanation:
Given : The probability that a customer will order a hamburger P(H)= 0.60.
The probability that a customer will order french fries P(F)= 0.50.
The restaurant has also determined that if a customer orders a hamburger, the probability the customer will also order fries : P(F|H)= 0.80.
Using conditional probability formula , for any event A (first event) and B (second event), we have:-
![P(B|A)=(P(A\cap B))/(P(A))\\\\\Rightarrow\ P(A\cap B)=P(A)*P(B|A)](https://img.qammunity.org/2020/formulas/mathematics/high-school/itohj7fhosyjh4d5l9drp9xy48gratj9kl.png)
Similarly, the probability that the order will include a hamburger and fries :-
![P(H\cap F)=P(H)* P(F|H)\\\\=0.60*0.80\\\\=0.48](https://img.qammunity.org/2020/formulas/mathematics/high-school/81qw4q4p0cqxrhk8c2alzw2fktmua9zt9s.png)
Hence, the probability that the order will include a hamburger and fries=0.48