Answer:
Probability that the surgery is successful for exactly 6 patients is 0.088.
Explanation:
The total number of patients is 10 and the probability of success is 0.8.
We have to determine the probability of success of the surgery of exactly 6 patients.
6 patients can be selected from 10 patients in
ways.
![nC_r=10C_6= \frac {10!}{6!(10-6)!}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v3rrgrfk85rn2xod2z372n9irs4chhura8.png)
![= (10!)/((6! * 4!))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pc4jix7khjsjqk5goqphw4wt6ges8pgr15.png)
![= \frac {3628800}{(720 * 24)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f2di0s1m7gioapzi2laoy3srxxfkj3c45u.png)
=210
Let us consider a combination SSSSSSFFFF where S denotes success and F denotes failure. The probability of this combination is given by
since the chance of success is 0.8 and chance of failure is 0.2.
There are 210 such different combinations possible and the probability of every combination is the same. So we have to sum up all the probabilities to determine the final probability.
Therefore the probability that surgery is successful for 6 patients is
![0.8^6 * 0.2^4 * 210=0.088](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4yk1csxky9fuq3d26jr6yomysgt574gaef.png)