Answer:
PM = 2,254 g / mol
Step-by-step explanation:
We must assume that the gas behaves like an ideal gas, in this case we can use the state equation
PV = n RT
Where P is the pressure, V is the volume, n is the number of moles, R the gas constant worth 8,134 J/mol K, the absolute temperature (degrees Kelvin)
let's start reducing everything to the international system of SI units
m = 2.5 g (1 kg / 1000g) = 2.5 10⁻³ kg
V = 5 liters (1 m3 / 1000 liter) = 5 10⁻³ m3
P = 1.2 atm (1,013 105 Pa / 1 atm) = 1.2 10⁵ Pa
T = 27 + 273 = 300K
Let's calculate the number of moles
n = PV / RT
n = 1.2 10⁵ 5 10⁻³ / (8.134 300)
n = 0.246 mol
To calculate the molecular weight we use a direct rule of proportions
PM = mass / n
PM = 2.5 10⁻³ / 0.246
PM = 2,254 kg / mol
PM = 2,254 g / mol