Question

An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iron are there in 52.5 grams of iron ore? Give only numerical value in the box below (no units)

Answer 1

There are 22.46 g of iron in 52.5 g of iron ore.

Step-by-step explanation:

Iron ore:

92.0 FeS₂ _______ 100 g iron ore

x _______ 52.5 g iron ore

x = 48.3 g FeS₂

Pyrite:

100 g FeS₂ ________ 46.5 g Fe

48.3 g FeS₂ ________ y

y = 22.46 g Fe