Question

Suppose the coefficient of static friction between the road and the tires on a car is 0.60 and the car has no negative lift. What speed will put the car on the verge of sliding as it rounds a level curve of 30.5 m radius?

Answer 1

Speed, v = 13.39 m/s

Step-by-step explanation:

It is given that,

The coefficient of static friction between the road and the tires on a car is 0.60,
`\mu_s=0.6`

Radius of the curve, r = 30.5 m

When the car is at the verge of sliding,

`(mv^2)/(r)=\mu_s\ mg`

v is the speed of the car

`v=√(\mu_s\ gr)`

`v=√(0.6* 9.8* 30.5)`

v = 13.39 m/s

So, the speed the car on the verge of sliding is 13.39 m/s. Hence, this is the required solution.