Answer:
25 m
Step-by-step explanation:
A student uses a spring to launch a marble vertically in the air. The mass of the marble is 0.002 kg and when the spring is stretched 0,05 m it exerts a force of 10 N. Therefore, the maximum height the marde can reach is 25 m.
Work to compress spring = gravitational potential energy of marble
W = PE
Fd = mgh
h = Fd / (mg)
Given F = 10 N, d = 0.05 m, m = 0.002 kg, and g = 10 m/s²:
h = (10 N) (0.05 m) / (0.002 kg × 10 m/s²)
h = 25 m
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