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Combining 0.301 mol Fe2O3 with excess carbon produced 11.6 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in moles?

1 Answer

4 votes

Answer:

The actual yield of iron is 0.208 moles.

Step-by-step explanation:

Given data:

Moles of Fe₂O₃ = 0.301 mol

Mass of iron = 11.6 g

Actual yield of iron in moles = ?

Solution:

Number of moles = mass / molar mass

Number of moles = 11.6 g/ 55.85 g/mol

Number of moles = 0.208 mol

It is the actual yield of iron in moles.

Theoretical yield can be calculated from given data.

One mole of Fe₂O₃ produce two mole two mole of iron.

0.301 moles will produce:

0.301× 2 = 0.602 mol

Theoretical yield in moles will be 0.602 moles.

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