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What equation is the inverse of y=2x^2-8?

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Explanation:

To get the inverse, swap the x- and y-variables, then solve for y. We should have the equation:
x = 2y^2 - 8

Solving for y:


y = 2x^(2) - 8
because
y + 8 = 2x^(2)
or
x =\sqrt(y +  8)/(2)

So on interchanging the variable, we get the equation:


x = 2y^2 - 8


x + 8 = 2y^2


y = \sqrt(x + 8)/(2)

User Krodak
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