Question

2. Cement has a density of 3.0 g/cm3. You must pour a cement walkway with the

measurements: 6 meters long by 1 meter wide by 10 centimeters thick. What is
the mass of this walkway? (Be careful ... notice that you will have to make some
metric conversions!) [Show your work!]

Answer 1

For this case we have to by definition:

`d = \frac {M} {V}`

Where:

d: It is the density

M: It's the mass

V: It is the volume

According to the data we have to:

`d = 3.0 \frac {g} {cm ^ 3}`

On the other hand we have that 1 meter is equivalent to 100 centimeters. Thus the measurements of the walkway are:

600 cm long, 100 cm wide and 10 cm thick. Looking for the volume we have:

`V = 600 * 100 * 10\\V = 600,000 cm ^ 3`

According to the formula we have:

`M = d * V\\M = 3.0 \frac {g} {cm ^ 3} * 600,000 cm ^ 3\\M = 1,800,000g`

Thus, the mass of the walkway is 1,800,000g

Answer:

1,800,000g