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Suppose the time it takes for a purchasing agent to complete an online ordering process is normally distributed with a mean of 8 minutes and a standard deviation of 2 minutes. Suppose a random sample of 25 ordering processes is selected. What is the standard deviation of the sampling distribution of mean​ times? (Round to one decimal place.)

User Jtitusj
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4 votes

Answer: 0.4

Explanation:

We know that the standard deviation of the sampling distribution of mean​ is given by:-


\sigma_x=(\sigma)/(√(n))

Given : Standard deviation :
\sigma= 2\text{ minutes}

Sample size : n= 25

Then, the standard deviation of the sampling distribution of mean​ times will be :-


\sigma_x=(2)/(√(25))\\\\\Rightarrow\ \sigma_x=(2)/(5)=0.4

Hence, the standard deviation of the sampling distribution of mean​ times=0.4

User Fragsworth
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