Question

A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.

(a) Neglecting air resistance, find the shell's horizontal range. 280,000 Correct: Your answer is correct. m
(b) Find the amount of time the shell is in motion.?

Answer 1

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Step-by-step explanation:

Is a parabolic movement so the velocity have two components:

`v = 1.74 x 10^(3)  ( (m)/(s) )`

`\alpha = 58`°

`v_(y) =v*Sen (\alpha )\\v_(x) =v*Cos (\alpha )`

`v_(y) =1740*Sen (58 )\\v_(x) =1740*Cos (58)`

`v_(y) = 1475.603 (m)/(s)\\v_(x) = 922.059 (m)/(s)\\`

`t= (2*v_(y) )/(g)`

`t= (2*1475.603 )/(9.8)`

`t= 301.143 s`

`v= (s)/(t) \\s= v_(x)*t`

`s= 922.059 (m)/(s) * 301.143 s`

`s = 277671.77 m`