Answer:
The maximum value of P=11 occurs at x=1 and y=4
Explanation:
we have
----> constraint A
----> constraint B
----> constraint C
----> constraint D
using a graphing tool
The solution is the shaded area
see the attached figure
The vertices of the solution area are
(0,0),(0,3),(1,4),(3,0)
Substitute the value of x and the value of y of each vertex in the objective function , to find out the maximum value of P
The objective function is

For (0,0) ----->

For (0,3) ----->

For (1,4) ----->

For (3,0) ----->

therefore
The maximum value of P=11 occurs at x=1 and y=4