Question

(3x 2 + 2x - 3)(x - 1) solve

Answer 1

`x=\frac{-1(+)√(10)} {3}`

`x=\frac{-1(-)√(10)} {3}`

`x=1`

Explanation:

we have

`(3x^(2)+2x-3)(x-1)`

Solve the quadratic equation

`(3x^(2)+2x-3)`

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`3x^(2)+2x-3=0`

so

`a=3\\b=2\\c=-3`

substitute in the formula

`x=\frac{-2(+/-)\sqrt{2^(2)-4(3)(-3)}} {2(3)}`

`x=\frac{-2(+/-)√(40)} {6}`

`x=\frac{-2(+/-)2√(10)} {6}`

`x=\frac{-2(+)2√(10)} {6}=\frac{-1(+)√(10)} {3}`

`x=\frac{-2(-)2√(10)} {6}=\frac{-1(-)√(10)} {3}`

therefore

The solutions of the equation

`(3x^(2)+2x-3)(x-1)`

are

`x=\frac{-1(+)√(10)} {3}`

`x=\frac{-1(-)√(10)} {3}`

`x=1`