Answer: Our required probability is 0.304.
Explanation:
Since we have given that
N = 21
Number of improperly drilled holes k = 4
Number of properly drilled holes = N-k= 21-4=17
Let X be the number of improperly drilled holes in a sample of 5.
We will use "Binomial distribution":
![P(X=5)=(^4C_0* ^(17)C_5)/(^(21)C_5)=0.304](https://img.qammunity.org/2020/formulas/mathematics/college/nkvli25w75hrgqc6u9p8q6dl120yrmgvzu.png)
So, our required probability is 0.304.