Question

(2x+4)^2 - (x-5)^2 = 26x
Please solve (explained)

Answer 1

Expand the squared binomials:

`(2x+4)^2=4x^2+16x+16`

`(x-5)^2=x^2-10x+25`

Then

`(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x`

`\implies3x^2-9=0`

`\implies3x^2=9`

`\implies x^2=3`

`\implies x=\pm\sqrt3`