Answer:
![speed=(195\ miles)/(3\ hours)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hoqr6cc3gmw615fos99rbl4r8ggt2rucyp.png)
![3\ hours=(195\ miles)/(speed)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a26bocowvz5k8gshplnyh3i5b50g8i8b5c.png)
![3\ hours*(speed)=195\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/csspnr01oki7jirsq1s7s4dc0ph075orr1.png)
Explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the distance in miles
y ----> the time in hours
![speed=(x)/(y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b8r8dg6e06s4c2ai12384zy3nlyhx3ep57.png)
we have
The distance is equal to subtract 35 miles from 230 miles
![x=230-35=195\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4efleb3fhmxmzlhxyh4nn1i9tddj41e0fr.png)
The time is equal to subtract 1:30 pm from 4:30 pm
![y=4:30\ pm-1:30\ pm=3\ hours](https://img.qammunity.org/2020/formulas/mathematics/middle-school/quqkdzm9idexodq8v12zls4jz2mjjgyuon.png)
substitute in the formula of speed
![speed=(195\ miles)/(3\ hours)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hoqr6cc3gmw615fos99rbl4r8ggt2rucyp.png)
Isolate 3 hours
![3\ hours=(195\ miles)/(speed)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a26bocowvz5k8gshplnyh3i5b50g8i8b5c.png)
Isolate 195 miles
![195\ miles=3\ hours*(speed)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g9uhrg0xt9x1jl6c9go8wdgmafe3n2ihse.png)