Question

Megan hits a softball into the stands. She rounds the bases and crosses home plate at 27km/h. Hey journey takes 6 seconds. What if Megan’s average acceleration

Answer 1

`a=1.25(m)/(sec^2)`

Step-by-step explanation:

we know that

The formula to calculate the acceleration is

`a=(V_2-V_1)/(t)`

we have

`V_1=0\\V_2=27\ km/h`

`t=6\ sec`

Remember that

`1\ km=1,000\ m\\1\ h=3,600\ sec`

Convert km/h to m/sec

`27\ km/h=27(1,000/3,600)=7.5\ m/sec`

Find the acceleration

`a=(7.5-0)/(6)`

`a=1.25(m)/(sec^2)`