Answer:
Ag+(aq) + Cl-(aq) -> AgCl(s)
Step-by-step explanation:
Given the next molecular equation:
AgNO3 (aq) + KCl (aq) -> AgCl(s) + KNO3 (aq)
To get the net ionic equation, first write separate ions for soluble electrolytes, those indicated with a '(aq)':
Ag+(aq) + NO3-(aq) + K+(aq) + Cl-(aq) -> AgCl(s) + K+(aq) + NO3-(aq)
And then cancel any ion on both sides of the previous equation, as follows:
Ag+(aq) + Cl-(aq) -> AgCl(s)