Question

Illustrate with a diagram. A force 150 newtons is inclined at 50 degrees to the horizontial direction. Find its component in the horizontial and vertical directions

Answer 1

The horizontal component is 96.42 N

The vertical component is 114.91 N

Step-by-step explanation:

A force 150 newtons is inclined at 50 degrees to the horizontal direction

We need to find its component in the horizontal and vertical directions

`F_(x)` is the horizontal component

`F_(y)` is the vertical component

Look to the attached figure:

The horizontal component
`F_(x)` is the product of F and cosine

the angle between F and the horizontal

The vertical component
`F_(y)` is the product of F and sine

the angle between F and the horizontal

→
`F_(x)` = F cos(50)

→
`F_(x)` = 150 cos(50)

→
`F_(x)` = 96.42 N

→
`F_(y)` = F sin(50)

→
`F_(y)` = 150 sin(50)

→
`F_(y)` = 114.91 N

The horizontal component is 96.42 N

The vertical component is 114.91 N