Question

A tennis ball is thrown up to a height of 26 m. Neglecting air resistance, with what initial

velocity was it thrown up with? Use Energy equations only

Answer 1

v = 22.58[m/s]

Step-by-step explanation:

To solve this problem we will use the principle of energy conservation, which tells us that potential energy is transformed into kinetic energy or vice versa.

`E_(kin)=E_(pot)`

We must remember that potential energy is defined as the product of mass by gravity by height.

`E_(pot)=m*g*h`

And the kinetic energy can be calculated by means of the following expression.

`E_(kin)=0.5*m*v^(2)\\`

Now equalizing the two equations we can determine the initial velocity.

`m*9.81*26=0.5*m*v^(2)\\255.06=0.5*v^(2)\\v=√(255.06/0.5)\\v=22.58[m/s]`