Answer: John's percentage error is 35.3 %.
Step-by-step explanation:
To calculate the percentage error, we use the equation:
![\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}* 100](https://img.qammunity.org/2020/formulas/chemistry/middle-school/i31lbe1sa6fbeojdslj4n93ce437nwvd37.png)
We are given:
Number of questions answered by John = 22
Total number of questions = 34
Putting values in above equation, we get:
![\%\text{ error}=(|22-34|)/(34)* 100\\\\\%\text{ error}=35.3\%](https://img.qammunity.org/2020/formulas/chemistry/middle-school/bvlekhx094osczo2o1wrhkh7i6hutxfdzv.png)
Hence, John's percentage error is 35.3 %.